A fair coin is tossed four times. What is the probability that the sequence of tosses is HHHT? ?
- PinkgreenLv 7hace 1 mes
- hace 1 mes
None of the answers so far, allow for unconventional results. Such as settling on edge or not landing at all. Oh - and they ignore schrodinger principle, where the coin is captured in flight and exists in an indeterminate state. But......this is why I got into trouble in high school math, for being a smartass. I wasn't - these are conditions a good software designer accounts for. Hey - I never even mentioned Heiseberg !!!
- busterwasmycatLv 7hace 1 mes
1 in 16. there are 16 possible orders that can arise. that is one of the 16. 2x2x2x2.
- Iggy RockoLv 7hace 1 mes
- ¿Qué te parecieron las respuestas? Puedes iniciar sesión para votar por la respuesta.
- MorningfoxLv 7hace 1 mes
There are 16 possible sequences, each with the same probability. So the probability of any particular sequence is 1 / 16.
- Wayne DeguManLv 7hace 1 mes
There are 2 possibilities that can occur at each toss.
so, 2 x 2 x 2 x 2 = 16 ways in total
H, H, H and T is a specific order and one unique combination
- !!!Lv 7hace 1 mes